in reply to
Multiple Combinatorics
My sets can overlap too. For exmaple I may have 4 sets like '0..7','16', '612',and '3..9'. I also need to eliminate duplicate items. In the case of overlapping sets, every resulting row should satisfy the initial condition. ie.. if I ask for 2 from '0..7' and 3 from '6..12', I should NOT have "6,7,6,7,8" or even "4,5,6,7,8" ( Here 0..7 has 4 entries rather than 2, as asked for.)
With those conditions, nothing will satisfy if you'd have to pick at least one from '1..6'. Because any pick from that set will be a possible pick from the set '0..7', making that the count of picks from that set will be off.
Re^2: Multiple Combinatorics by aartist (Scribe) on Apr 15, 2012 at 15:45 UTC 
If '07' has less number of picks compared to '16', then we will have no solution at all. But, it is possible that ('07','16') has (3,2) picks or even (2,2) picks respectively. In the first case there will be exactly 1 selection from 0 and 7 in any solution. In the 2nd case, 0 and 7 will not be selected in any solution.  [reply] 

Care to clarify that? Maybe add some examples? Cos like JavaFan, I don't get it.
As soon as you pick any two values from group 2 (1..6), you've also already picked two values from group 1 (0..7), so there is no way to comply with your "every resulting row should satisfy the initial condition" requirement.
You would either a) a pick two from both groups and therefore have 4 from the larger group; or b) pick nothing from the larger group, in which case you have nothing from the larger group.
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Yes:
if Group B (1..6) is subset of Group A(0..7) and Pick(B)=2 is equal to Pick(A)=2 then we apply 'b): pick nothing from larger group';
In this case, we still have picked 2 values from larger group automatically, which holds the initial condition. Only thing that '0' and '7' won't be picked at all in any resultset. ( from the given data).
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