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Re^4: How regex works in array mode?

by astronogun (Sexton)
on Apr 26, 2012 at 09:12 UTC ( #967276=note: print w/ replies, xml ) Need Help??

in reply to Re^3: How regex works in array mode?
in thread How regex works in array mode?

I already replace it and the output is:


but it doesn't print the "ip:" Is it possible to print the next value in the array? Thanks

or is this output possible?

ip: ip:

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Re^5: How regex works in array mode?
by JavaFan (Canon) on Apr 26, 2012 at 10:02 UTC
    Perhaps you haven't replaced it correctly?
    use 5.010; my @lines = ("ip:", "ip:" =~ /(ip:[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3})/); say for @lines; __END__ ip: ip:
    Do note that ip: is in @lines only because the pattern matches the entire string. And do note that "ip:" is not subject to any matching. In fact, the assignment to @lines is equivalent with:
    my @lines; $lines[0] = "ip:"; push @lines, $1 if "ip:" =~ /(ip:[0-9]{1,3}\.[0-9]{1,3}\. +[0-9]{1,3}\.[0-9]{1,3})/;

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