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Re^2: 0 illegal modulus?

by Anonymous Monk
on May 01, 2012 at 03:35 UTC ( #968202=note: print w/ replies, xml ) Need Help??


in reply to Re: 0 illegal modulus?
in thread 0 illegal modulus?

This seems to work great, thank you!

#use DateTime::Util::Calc qw(mod); #sub mod { $_[1]*1 ? $_[0] % $_[1] : 0);} sub mod { my($x)=$_[0]; my($y)=$_[1]; while($x >= 0){ $x-=$y; } $x+=$y; return($x); }


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