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Re^2: Update references

by Anonymous Monk
on May 13, 2012 at 17:46 UTC ( #970308=note: print w/ replies, xml ) Need Help??


in reply to Re: Update references
in thread Update references

The point is, that I don't want to renew the reference. I'm using this kind of reference for Tk-Checkbuttons and I'd have to recreate all of them (and there a quite a few).

I thought, that a reference points to a place in your memory and doesn't care what's written in there. But it looks like I can't replace that piece of data by modifying the original array. Too me it looks a bit odd.


Comment on Re^2: Update references
Re^3: Update references
by Eliya (Vicar) on May 13, 2012 at 22:29 UTC
    But it looks like I can't replace that piece of data by modifying the original array.

    Of course you can, but you must not destroy the internal reference of the array slot [0] to the scalar originally stored in it.  If you do so, you have no access to that scalar any longer via $a[0].

    Change @a = ('a','b','c') to  pop @a; @a[0..2] = qw(a b c); and things will work fine.

    In the former case, 3 new scalars are being placed into the array slots, while in the latter case, the old scalars are being modified.

    #!/usr/bin/perl -w use strict; print "--------Trying with arrays-------\n"; my @a = (0, 1, 2, 3); my $ar = \@a; # Array reference my $air = \$a[0]; # Reference to member of an array print "Define array >@a<\nCreate a reference to \$a[0]\n"; print "array ref: >@$ar< \n"; print "array index ref: >$$air<\n"; pop @a; @a[0..2] = qw(a b c); print "Change array to >@a<\n"; print "array ref: >@$ar< \n"; print "array index ref: >$$air<\n"; # <--- I'd like to get "a" here __END__ --------Trying with arrays------- Define array >0 1 2 3< Create a reference to $a[0] array ref: >0 1 2 3< array index ref: >0< Change array to >a b c< array ref: >a b c< array index ref: >a<

    Your misunderstanding is that you think Perl works like C, i.e. that references directly point to the memory locations where the actual data is stored.  This is not how Perl works.

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