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if statement problem using mysql

by CreationP (Initiate)
on May 31, 2012 at 14:55 UTC ( #973540=perlquestion: print w/ replies, xml ) Need Help??
CreationP has asked for the wisdom of the Perl Monks concerning the following question:

I'm using a table named 'options' which has 1 field with the name 'log' and one record which can be only 1 or 0. Default value is 1. I want to enable or disable logging to my progra, using the following code:

if ($choise ==6){ $sql1 = "select * from scanner.options"; $sth1 = $dbh ->prepare($sql1); $sth1->execute or die "SQL Error: $DBI::errstr\n"; while (@option - $sth1 ->fetchrow_array()){ $log = $option[0]; } if ($log == 1){ print "Logs = 1"; print "\n\nWould you like to disable logging? (press 1 for yes + or anything else for no): "; my $o_log= <STDIN>; if ($o_log == 1){ my $sql = "UPDATE options SET log=0 WHERE log=1"; $sth = $dbh->prepare($sql); $sth->execute or die "SQL Error: $DBI::errstr\n"; } } else{ print "Logs = 0"; print "\n\nWould you like to enable logging? (Press 1 for yes +or anything else for no): "; my $o_log= <STDIN>; if ($o_log == 1){ my $sql = "UPDATE options SET log=1 WHERE log=0"; $sth = $dbh->prepare($sql); $sth->execute or die "SQL Error: $DBI::errstr\n"; } } }

Using this code I cannot get the program to go into the first if function ($log == 1). I also tried with if ($option[0] == 1) and it still does not work. My value in the mysql table is 1. Why is it not working and how can I make it work? Thank your for your time.

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Re: if statement problem using mysql
by Eliya (Vicar) on May 31, 2012 at 15:05 UTC
    while (@option - $sth1 ->fetchrow_array()){ ^

    Is this a typo?

      Dear Eliya, No it wasn't a typo. I don't know why but I thought it was the correct form. I changed the '-' to '=' and worked as intended. Thank you very much for scanning my code and finding out the error. You guys here in perlmonks are lifesavers!

Re: if statement problem using mysql
by toolic (Bishop) on May 31, 2012 at 15:04 UTC

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