Approximate Delivery Date from USPS

[remya]

Hi, How can i calculate the approximate delivery date from usps using perl. Is there any perl module for the same.

[marto]

Did you look at the API section of their website? A CPAN search shows several results including Business::US::USPS::WebTools.

[remya]

Thanks your reply.. But I coudn't see a solution for delivery date there.

[marto]

Have you examined what their APIs gives you access to?

[zentara]

the approximate delivery date from usps

I order online very often, and I must say for the USPS, approximate is the right term to describe their tracking system. I've checked USPS tracking many times. Sometimes it said the package was already delivered, and it still didn't come for a week. Other times, it said delivery was next week, and it came that day.

In comparison, UPS tracking is right on time, almost to the minute.

So for the USPS, tracking is essentially useless, they need some Perl programmers and some scanners. :-)

[Illuminatus]

So Business::Shipping::USPS_Online::Tracking isn't what you're looking for? However, I agree with zentara; I don't think you'd be far off with:

use DateTime::Event::Random;
use strict;

my $dt;
if (exists (USPS)) {  # they could be bankrupt
  do {
     $dt = DateTime::Event::Random->datetime( after => DateTime->now )
+;
  } until $dt->day_of_week != 7;  # sunday
} else {
    print "Never, sorry\n";
}

fnord

[ww]

# they could be bankrupt

<rant extended...> Surely someone there (or in Congress) recognizes that they're on the same course the railroads took in the '50s, et seq.:
• Reduced service -> customers find alternate solutions ->reduced service
• Abandonments
• Pricing favoring a customers with alternates, and discouraging customers with limited alternatives
• An assumption that technological advances (aka: www) provide inexpensive and efficient service to customers not targetted for service (ie, in the RR analogy, 'not on the main line').

Anyone else love what's happening as USPS?

[Anonymous Monk]

perl -e 'print int(rand()*1000) . " days";'

;-)