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symboltable problem

by morgon (Deacon)
on Jun 20, 2012 at 16:53 UTC ( #977406=perlquestion: print w/ replies, xml ) Need Help??
morgon has asked for the wisdom of the Perl Monks concerning the following question:

Hi monks,

I would like to understand why the following script does not behave as expected.

In the script I had expected that $Bubba::abba would become an alias for $Hubba::abba, but that does not seem to be the case - so evidently %Bubba:: = %Hubba:: is not doing what I thought it would do....

Can someone explain the behaviour to me?

use strict; use Data::Dumper; # put something in package "Hubba" $Hubba::abba = "zappa\n"; # assign Hubba-symtable to Bubba-symtable %Bubba:: = %Hubba::; # verify that they are the same print Dumper(\%Hubba::); print Dumper(\%Bubba::); # use 2 ways to print $abba from Hubba print ${*Hubba::abba{SCALAR}}; # works print $Hubba::abba; # works print "and now Bubba:\n"; print ${*Bubba::abba{SCALAR}}; # prints nothing print $Bubba::abba; # print nothing

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Re: symboltable problem
by Anonymous Monk on Jun 20, 2012 at 17:31 UTC

    Its called magic :) There is a reason modules on cpan for this, see alias , namespace, and stash

    use Data::Dump; $FOO::ONE = 1; *BAR:: = *FOO::; $BAR::ONE = 2; dd \%BAR::, \%FOO::; dd \*BAR::; __END__ do { my $a = { ONE => *FOO::ONE }; $a->{ONE} = \1; ($a, $a); } do { my $a = \*main::FOO::; *{$a} = { ONE => *FOO::ONE }; *{$a}{HASH}{ONE} = \1; $a; }

    use Data::Dump::Streamer; $FOO::ONE = 1; *BAR:: = *FOO::; $BAR::ONE = 2; Dump \%BAR::, \%FOO::; Dump \*BAR::; __END__ $HASH1 = { ONE => *FOO::ONE }; *FOO::ONE = \do { my $v = 1 }; $HASH2 = $HASH1; $GLOB1 = \*{'::FOO::'}; *{'::FOO::'} = { ONE => *FOO::ONE }; *FOO::ONE = \do { my $v = 1 };
      My problem is not to learn how to achieve an alias but to understand the behavour of the script supplied.
Re: symboltable problem
by Anonymous Monk on Jun 20, 2012 at 18:00 UTC

    Here is some revelation

    print 2, because *BAR::ONE (SCALAR slot included ) is aliased to *FOO::ONE

    perl -e" $FOO::ONE = 1; *BAR::ONE = *FOO::ONE ; $BAR::ONE = 2; print +$FOO::ONE "

    prints 1 because *BAR::ONE slots isn't aliased to *FOO::ONE slots

    $ perl -e" $FOO::ONE = 1; *BAR:: = *FOO:: ; $BAR::ONE = 2; print $FOO +::ONE 1
      Ok, call me stupid but I don't get what you are trying to say.

      I re-phrase my question:

      For package "Hubba", it's symbol table is stored in a hash %Hubba:: that maps symbol-names to typeglobs.

      So when I do %Bubba:: = %Hubba:: (I am NOT doing *Bubba::=*Hubba::) the whole symbol-to-typeglob mapping is copied to another hash (which happens to be the symbol-table of another package).

      So why does that then not create aliases?

      I can do this:

      our $var = "zappa"; $Bubba::{abba} = *var; print $Bubba::abba;
      which shows that I can create variables by manipulating the symbol-table. Why does that not happen in my script?

      Can someone explain that in plain english without using the word "magic"?

        I think the problem is that %Bubba:: = %Hubba:: is creating a new hash, which destroys the binding of $Bubba::abba to the original hash set up at compile time of the latter expression.  This reasoning is based on the observation that both of the following work fine:

        #!/usr/bin/perl use strict; $Hubba::abba = "zappa\n"; %Bubba:: = %Hubba::; # compile time deferred eval 'print $Bubba::abba';
        #!/usr/bin/perl use strict; $Hubba::abba = "zappa\n"; # copying via hash slice doesn't create new hash @Bubba::{keys %Hubba::} = @Hubba::{keys %Hubba::}; # or: @Bubba::{keys %Hubba::} = values %Hubba::; print $Bubba::abba;

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