Re: Style - how to give class method call as parameter

[Athanasius]

in reply to Style - how to give class method call as parameter

Number 3a:

my $success = $self->do_sub_with_timeout( $deployer->extend_order_leas
+e( $order, $end_date ),
                                          $timeout );

But there’s nothing wrong with Number 1.

Update: Seems I missed the point of the question. Thanks to Boldra and choroba for pointing out that my ‘solution’ preempts the timeout.

[Boldra]

That's not going to work, extend_order_lease will be executed before do_sub_with_timeout gets called, so there'll be no chance for it to interrupt.

OP: How much code is in do_sub_with_timeout? Since the subroutine/method call is making it less readable, maybe there's no benefit in putting it in a subroutine? Maybe what you really want is a sub like handle_timeout which gets called if the timeout is exceeded.

[choroba]

That's not the same. You are calling the method, not passing a reference to it.