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Re^2: Problems with formatting the results of my regex

by superwombat (Novice)
on Jul 07, 2012 at 06:38 UTC ( #980447=note: print w/ replies, xml ) Need Help??


in reply to Re: Problems with formatting the results of my regex
in thread Problems with formatting the results of my regex

Fantastic! Thanks for the quick response. I tested the new code and it's working perfectly now. I still can't understand why the \r was getting captured in $2, since that portion supposedly should end with \d* zero or more digits. In any case, I'm glad it's fixed now.


Comment on Re^2: Problems with formatting the results of my regex
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Re^3: Problems with formatting the results of my regex
by monsoon (Pilgrim) on Jul 07, 2012 at 06:46 UTC
    .? in (\-?\d+.?\d*) matched \r

      Yes, most (all?) of those . characters in the regex should be changed to \. so that they match just "." not /[^\n]/. You can also use [.]

      - tye        

        Provided sample line has only 1 literal . character in it. I think only this part (\d+ \d+:\d+:\d+.\d+) and perhaps this one (\-?\d+.?\d*) (if it really meant to match floating point numbers) can have . character replaced with \. but not the other two.
      Ah.... That's part of my problem then. I intended .? to mean literally "zero or one decimal points" That was a rookie mistake.

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