Re^2: Problems with formatting the results of my regex

in reply to Re: Problems with formatting the results of my regex
in thread Problems with formatting the results of my regex

Fantastic! Thanks for the quick response. I tested the new code and it's working perfectly now. I still can't understand why the \r was getting captured in $2, since that portion supposedly should end with \d* zero or more digits. In any case, I'm glad it's fixed now.

Comment on Re^2: Problems with formatting the results of my regex
Re^3: Problems with formatting the results of my regex by monsoon (Monk) on Jul 07, 2012 at 06:46 UTC
`.?` in `(\-?\d+.?\d*)` matched `\r`	[reply] [d/l] [select]
Re^4: Problems with formatting the results of my regex (\.) by tye (Cardinal) on Jul 07, 2012 at 07:16 UTC
Yes, most (all?) of those `.` characters in the regex should be changed to `\.` so that they match just `"."` not `/[^\n]/`. You can also use `[.]` - tye	[reply] [d/l] [select]
Re^5: Problems with formatting the results of my regex (\.) by monsoon (Monk) on Jul 07, 2012 at 07:41 UTC
Provided sample line has only 1 literal . character in it. I think only this part `(\d+ \d+:\d+:\d+.\d+)` and perhaps this one `(\-?\d+.?\d*)` (if it really meant to match floating point numbers) can have . character replaced with \. but not the other two.	[reply] [d/l] [select]
Re^4: Problems with formatting the results of my regex by superwombat (Initiate) on Jul 07, 2012 at 08:11 UTC
Ah.... That's part of my problem then. I intended .? to mean literally "zero or one decimal points" That was a rookie mistake.	[reply]


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Re^2: Problems with formatting the results of my regex

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