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get list of files matching part of file name

by doubledecker (Scribe)
on Jul 11, 2012 at 12:13 UTC ( #981099=perlquestion: print w/ replies, xml ) Need Help??
doubledecker has asked for the wisdom of the Perl Monks concerning the following question:

Hello Monks

any ideas of how to get list of files matching part of filename. ex: get filenames sample.txt or sample123.txt

use strict; use warnings; use File::Basename; use Data::Dumper; my @files = glob(".* *"); my $dir = '/home/test'; foreach my $file ( @files ) { next if ( $file eq '.' or $file eq '..' ); my @matches = glob("$dir/$file*"); if ( @matches ) { print Dumper(@matches); } }

This isn't doing what i expected. Any ideas are appreciated

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Re: get list of files matching part of file name
by RichardK (Priest) on Jul 11, 2012 at 12:37 UTC

    you didn't say what you expect your code to do, so it difficult to offer any useful suggestions, other than glob('sample*.txt')

    Maybe my @files = glob (".* *") doesn't do what you think it does?

    see glob

      I used glob to list all the files in my current directory and using those list of files i'm trying to find out matching files in other directory

        A couple of points:

        (1) In the foreach loop, $file contains a filename together with its path and extension. To extract just the name part, you need something like:

        (my $basename = fileparse($file)) =~ s/ \. .* $ //x;

        which uses the fileparse function from File::Basename to extract the filename, then removes the extension (if any).

        (2) print Dumper(@matches); will print each match on a separate line. You would probably be better off with something like this:

        printf "'%s' matches: %s\n", $basename, join(', ', @matches);

        HTH,

        Athanasius <°(((><contra mundum

Re: get list of files matching part of file name
by zentara (Archbishop) on Jul 11, 2012 at 14:23 UTC
    Here is a File::Find solution
    #!/usr/bin/perl # non recursive case insensitive search down # thru current directory for pattern in filenames. use warnings; use strict; use File::Find; $|++; my $search = $ARGV[0] or die "need search pattern $!\n"; my $path = '.'; my $regex = qr/\Q$search\E/i; find (sub { #prevent recursion into subdirs my $n = ($File::Find::name) =~ tr!/!!; #count slashes in file return $File::Find::prune = 1 if ($n > 1); return if -d; # return unless (-f and -T ); # limit to text files print "$File::Find::name\n" if /$regex/; }, $path);

    I'm not really a human, but I play one on earth.
    Old Perl Programmer Haiku ................... flash japh
Re: get list of files matching part of file name
by Anonymous Monk on Jul 11, 2012 at 16:15 UTC

    What a strange way to use glob(). You're better off with proper use of readdir():

    # open current directory for reading opendir my $dh, '.' or die; # iterate through the entries while (my $dir = readdir($dh)) { # your code here } closedir $dh;

    If you want to use glob() properly, you need to do glob("*/*sample*") to get every file in the current directory's immediate subdirectories with 'sample' in its name.

    There seems to be at least one real bug in your code: You aren't in /home/test when you do the glob.

Re: get list of files matching part of file name
by Anonymous Monk on Jul 11, 2012 at 17:02 UTC
    use File::Find::Rule; my @filenames = qw[ sample.txt sample123.txt ]; my $reFilenames = join '|', map quotemeta, @filenames; $reFilenames = qr/$reFilenames/i; my @files = find( 'file' => 'name' => $reFilenames, 'maxdepth' => 1, 'in' => $dir );

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