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Re^2: Archive::Zip - How to selectively copy files from one archive to another one?

by Gigabyte1907 (Initiate)
on Aug 11, 2012 at 18:08 UTC ( #986914=note: print w/replies, xml ) Need Help??


in reply to Re: Archive::Zip - How to selectively copy files from one archive to another one?
in thread Archive::Zip - How to selectively copy files from one archive to another one?

Hello Mr. Muskrat and thanks for your reply.

I didn't have the code that I tried and I tried so many things that I decided to start from scratch... ;-)

Anyway I have tried your answer and first of all, it doesn't really answer the question because I was asking about selectively extract from one Zip and copy the files into another Zip. Which mean that I do not know yet what the file list is.

Based on your example and trying to remember what I did before, here is the code that I came up with:

use strict; use Archive::Zip qw( :ERROR_CODES :CONSTANTS ); my $oldfile = 'oldzip.zip'; my $newfile = 'newzip.zip'; my $oldzip = Archive::Zip->new(); $oldzip->read($oldfile) == AZ_OK or die 'read error'; my $newzip = Archive::Zip->new(); # Getting the list of selected files my @FileMembers123 = $oldzip->membersMatching("123.*\.xml"); foreach my $file (@FileMembers123) { $oldzip->extractMember($file); $newzip->addFile($file); } $newzip->writeToFileNamed( $newfile ) == AZ_OK or die 'error somewhere +';

When I try to execute this code, I have this error message:

Can't call method "desiredCompressionLevel" on an undefined value at c:/perl/lib/Archive/Zip/Archive.pm line 249

When I try to print the content of the array @FileMembers123, this is what I get:

Archive::Zip::ZipFileMember=HASH(0x2f122f4)
Archive::Zip::ZipFileMember=HASH(0x2f124c4)
Archive::Zip::ZipFileMember=HASH(0x2f12694)
Archive::Zip::ZipFileMember=HASH(0x2f12864)
Archive::Zip::ZipFileMember=HASH(0x2f25a2c)
Archive::Zip::ZipFileMember=HASH(0x2f2a804)
etc...

It seems that I cannot get the file names using the command my @FileMembers123 = $oldzip->membersMatching("123.*\.xml");.

If I could generate the list of the files (using a matching pattern) in my old Zip without unzipping it, it would probably work.

Thanks again!

Replies are listed 'Best First'.
Re^3: Archive::Zip - How to selectively copy files from one archive to another one?
by Mr. Muskrat (Canon) on Aug 12, 2012 at 21:53 UTC

    It's all explained rather well in the docs. Archive::Zip

    addFile is expecting a filename not an Archive::Zip::ZipFileMember object. Try this instead:

    #!perl use strict; use warnings; use Archive::Zip qw( :ERROR_CODES :CONSTANTS ); # Include actual filenames in the next two lines my $oldfile = 'oldzip.zip'; my $newfile = 'newzip.zip'; my $oldzip = Archive::Zip->new(); $oldzip->read( $oldfile ) == AZ_OK or die 'read error'; print "$oldfile contains the following files:\n"; print " $_\n" for $oldzip->memberNames(); print "\n"; my $newzip = Archive::Zip->new(); my @wanted = $oldzip->membersMatching( '123.*\.xml' ); for my $member ( @wanted ) { print "Extracting ", $member->fileName(), " from $oldfile and addi +ng to $newfile\n"; $oldzip->extractMember( $member ); $newzip->addMember( $member ); } print "\n"; $newzip->writeToFileNamed( $newfile ) == AZ_OK or die 'error somewhere +'; print "$newfile contains the following files:\n"; print " $_\n" for $newzip->memberNames(); __END__ # Sample output oldzip.zip contains the following files: 123a.xml 123b.xml 234c.xml Extracting 123a.xml from oldzip.zip and adding to newzip.zip Extracting 123b.xml from oldzip.zip and adding to newzip.zip newzip.zip contains the following files: 123a.xml 123b.xml

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