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Re: correct angle on tackling a problem

by MidLifeXis (Prior)
on Aug 24, 2012 at 18:39 UTC ( #989608=note: print w/ replies, xml ) Need Help??


in reply to correct angle on tackling a problem

Be aware that

$dst = $line =~ /SG-HTTP-Service (\d+.\d+.\d+.\d+)/g;
does not do what you think it does. You need to escape the '.' if you want it to be literal in a regexp. If you do not, the '.' means 'any character'. This exists in multiple locations in your script.

--MidLifeXis


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Re^2: correct angle on tackling a problem
by diamondsandperls (Beadle) on Aug 24, 2012 at 19:03 UTC
    thanks for the heads up on my regex never thought of it like that but what you say does make sense bc . does many any character.

    Not sure how to apply the logic foo() unless $seen{$key}++; to the current code?

      diamondsandperls:

      He means logic like:

      my %seen; for my $key (0 1 2 1 2 3 2 3 4 3 4 5) { print $key unless $seen{$key}++; }

      This (untested) script should just print the values 0 through 5 in order. The $key value is just the data you use to tell whether it's identical or not. When you first check the %seen hash for the value 0, there won't be an entry for zero, so the print will execute. The line also increments the value in the %seen hash to 1, so the next time you see 0 it *won't* print.

      You just need the %seen hash, the data you use for the $key, and an action you want to control.

      ...roboticus

      When your only tool is a hammer, all problems look like your thumb.

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