perl CGI form ignores value

I have some code where default values for textfields() are supplied from a database.

I have occasion to call the app with a different value, but I want the different value to be ignored and the default value from the database to be used.

I've tried setting it with -override in the textfield() as well as calling param() to set it specifically, but the output on the webpage is always the POST-supplied information instead of the -value=>"db data".

Any idea on how I can make it listen to me?

For now I have forced a redirect so it pulls data from the database (as there is no supplied data). It works fine, but it seems like a hack. It seems like there should be a way for the form value to be programmed, ignoring the POST parameter.

Comment on perl CGI form ignores value
Re: perl CGI form ignores value by Anonymous Monk on Sep 17, 2012 at 02:12 UTC
It seems like there should be a way for the form value to be programmed, ignoring the POST parameter. You mean, like tell CGI.pm not to read any vars? Sure `CGI->new({});` It will still read cookies as those come via %ENV	[reply] [d/l]
Re: perl CGI form ignores value by rjt (Friar) on Sep 17, 2012 at 03:10 UTC
There are several ways you can do this, but the following is reasonably efficient, and hopefully your parameter list is relatively small anyway: `my $q = new CGI; my %vars = $q->Vars; # Fetch all CGI parameters my %db_vars = pop_defaults(); # Fetch from database # Override defined values from database $vars{$_} = $db_vars{$_} for (keys %db_vars); # Fetch all defaults from the DB and return as a hash ref sub pop_defaults { my $r = { }; ... return $r }` [download] You can also simply loop through the params: `$vars{$_} = $db_vars{$_} // $q->param($_) for ($q->param);` [download] Finally, if you prefer to merge hash slices: `%vars{keys %db_vars} = values %db_vars;` [download]	[reply] [d/l] [select]


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perl CGI form ignores value

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