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Re: How to create loop in perl dynamically

by grizzley (Chaplain)
on Sep 26, 2012 at 13:25 UTC ( #995767=note: print w/replies, xml ) Need Help??


in reply to How to create loop in perl dynamically

I would create array containing max values for each loop and iterate over array.
#!perl -l @maxvalues = (2, 5, 3); $input = 3; my @ids = (0) x $input; # assuming all loops start with 0 while(!$end) { # do something print "[@ids]"; # increase values starting from end of ids array $index = $#ids; while(1) { $ids[$index]++; if($ids[$index]<=$maxvalues[$index]) { last } else { # we reached limit on loop pointed by $index $ids[$index] = 0; $index--; if($index<0) # check stop condition { $end = 1 } } } }

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Re^2: How to create loop in perl dynamically
by adithi (Initiate) on Sep 26, 2012 at 14:09 UTC
    Thank u. But I didnt the logic used here.
      Then spend some time analyzing it, understanding the code you want to use is very important. If you won't get it (actually even if you will) - use module, as advised here: Re: How to create loop in perl dynamically

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