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Simple regex question

by zuma53 (Beadle)
on Sep 28, 2012 at 18:09 UTC ( #996261=perlquestion: print w/ replies, xml ) Need Help??
zuma53 has asked for the wisdom of the Perl Monks concerning the following question:

I am using \w+ to filter words in a syntax.
All letters: good Letters and numbers: good All numbers: bad
How can I set up a regex to say \w+ except \d+?

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Re: Simple regex question
by BrowserUk (Pope) on Sep 28, 2012 at 18:13 UTC

    Almost exactly the way you described it:

    print "$_: ", /^\w+$/ && !/^\d+$/ ? 'Good' : 'Bad' for qw[ abc a1c 1b3 + 123 ];; abc: Good a1c: Good 1b3: Good 123: Bad

    Or if you insist on a single regex:

    print "$_: ", /^(?=.*[a-zA-z])\w+$/ ? 'Good' : 'Bad' for qw[ abc a1c 1 +b3 123 ];; abc: Good a1c: Good 1b3: Good 123: Bad

    Though it is doubtful if it is any more efficient; and is certainly less clear.


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Re: Simple regex question
by bart (Canon) on Sep 29, 2012 at 09:05 UTC
    /^(?=.*[a-z])\w+$/i
    (translation: all word characters, but at least a letter)

    You don't say if you think underscores are acceptable...

    /^(?=.*[a-z])(?!.*_)\w+$/i
    (translation: All word characters, but at least a letter, an no underscore)

    There.

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