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Re: $a <=> $b

by tobyink (Abbot)
on Oct 09, 2012 at 18:57 UTC ( #998055=note: print w/ replies, xml ) Need Help??


in reply to $a <=> $b

roboticus' answer is correct. The documentation for the special variables $a and $b is in perlvar.

perl -E'sub Monkey::do{say$_,for@_,do{($monkey=[caller(0)]->[3])=~s{::}{ }and$monkey}}"Monkey say"->Monkey::do'


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