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Re: Another Pattern Matching Question

by kcott (Abbot)
on Oct 12, 2012 at 16:51 UTC ( #998745=note: print w/ replies, xml ) Need Help??


in reply to Another Pattern Matching Question

G'day surib,

Welcome to the monastery.

You show the original pattern as: /3B41|2RT\.\d{10}\.\d+\.bin/. Making allowances for the lack of <code> tags, I've assumed 1|2 should be [0|1|2] - this gives a regex which matches the first filename. However, making the same assumption a few lines further down, /3B4[0|1|2]RT\.\d{10}\.\d+R?\.bin/ should have matched both filenames. Was my assumption wrong? Have you shown the correct filenames? Did you type some other part of the regex incorrectly? Please clarify.

-- Ken


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Re^2: Another Pattern Matching Question
by surib (Initiate) on Oct 12, 2012 at 17:25 UTC
    Sorry about not using the
    . Here's my code when I actually hard code the '7R', yet it still fails. + I must be missing something else? <br> <code> my ($product, $year, $month, $day, $hour, $suffix, $ver ) = spl +it /\./, $fileName; # test file name--naming convention is '<product>.<year>.<month>.<day> +.<hour>.bin' if ($fileName =~ /3B4[0|1|2]RT\.\d{10}\.\7R\.bin/) { ($product, $year, $month, $day, $hour, $ver) = ($fileName =~ /(3B4.RT)\.(\d{4})(\d\d)(\d\d)(\d\d)\.(7R\)\.bin/) +; $version = sprintf "%03d", $ver; # a little confusing, $version +is global # $ver is local } elsif ($fileName =~ /3B4\dRT\.\d\d\d\d\.\d\d\.\d\d.\d\dz\.bin/) { ($product, $year, $month, $day, $hour, $suffix) = split /\./, $fil +eName; } else { print STDERR "($0,$$) ERROR: invalid file name--'$fileName'\n" if + $opt_v; exit 2; }
      Or like this: (I've tried so many combinations I'm confusing myself!)
      if ($fileName =~ /3B4[0|1|2]RT\.\d{10}\.7R.bin/) { ($product, $year, $month, $day, $hour, $ver) = ($fileName =~ /(3B4.RT)\.(\d{4})(\d\d)(\d\d)(\d\d)\.(7R)\.bin/); $version = sprintf "%03d", $ver; # a little confusing, $version +is global # $ver is local
        If you just want to match 0,1, or 2 and not "|", then your character class should be [012], not [0|1|2].

      Your solution which adds R? to the original regex was on the right track and achieves what you want, albeit poorly:

      $ perl -Mstrict -Mwarnings -E 'my $fileName; my $re = qr{3B4[0|1|2]RT\.\d{10}\.\d+R?\.bin}; $fileName = "3B40RT.2000033121.7.bin.gz"; say +($fileName =~ /$re/) ? "match" : "no match"; $fileName = "3B40RT.2000033121.7R.bin.gz"; say +($fileName =~ /$re/) ? "match" : "no match"; ' match match

      I don't think you understand character classes or alternation (perhaps both). Where you're trying to match a 0, 1 or 2 in the same position, [0-2] would be far better than [0|1|2] (which is trying to match a 0, pipe, 1, pipe or 2 in the same position) - the 2nd pipe is redundant and the 1st pipe isn't wanted anyway. So, here's an improved version:

      $ perl -Mstrict -Mwarnings -E 'my $fileName; my $re = qr{3B4[0-2]RT\.\d{10}\.\d+R?\.bin}; $fileName = "3B40RT.2000033121.7.bin.gz"; say +($fileName =~ /$re/) ? "match" : "no match"; $fileName = "3B40RT.2000033121.7R.bin.gz"; say +($fileName =~ /$re/) ? "match" : "no match"; ' match match

      Recommended reading:

      -- Ken

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