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Hi Perl Monks,

It might be a silly question but I am at my wit's end to get the desired result in the last array (line 19). I have written a perl script (given below) to count the number of 4-letter fragments in a 15-letter word. My interest is to assign the length of each fragment as an element in the final array i.e. @newarray. The new array at line 19 should show the elements (4 4 4) but I am getting only one 4. Is it possible to get the correct result from the newarray as (4, 4, 4)?

Here goes the perl script:

```#!/usr/bin/perl
use warnings;
\$word="ABCDEFGHIJKLMNO";
## Determining the number of 4-letter Fragments:
\$a=length(\$word);\$four=4;  # Line 5
\$frag_Num1=\$a/\$four;\$frag_Num=int\$frag_Num1;
print"\n Total Fragments= \$frag_Num\n\n";
print"\n\n The 4-Letter Fragments are:\n\n";
\$frag=0;
while (\$word=~ /(.{4}?)/igs)   # Line 10
{\$frag++;
\$b=\$&;\$pos=\$-[0]+1;
\$leng=length(\$b);
print"\n Fragment: \$&; Fragment Number: \$frag of length \$leng letters
+ Starting at position: \$pos\n";
print"\n Its length= \$leng Letters;\n\n";  # Line 15
\$newlist=\$leng;
}
@newarray="\$newlist";
print"\n Newarray (should be 4 4 4): @newarray\n\n"; # Line 19
exit;

The cmd has shown the correct results except for the last line:

```Total Fragments= 3

The 4-Letter Fragments are:

Fragment: ABCD; Fragment Number: 1 of length 4 letters Starting at po
+sition: 1

Its length= 4 Letters;

Fragment: EFGH; Fragment Number: 2 of length 4 letters Starting at po
+sition: 5

Its length= 4 Letters;

Fragment: IJKL; Fragment Number: 3 of length 4 letters Starting at po
+sition: 9

Its length= 4 Letters;

Newarray (should be 4 4 4): 4

The last line should look like:

Newarray (should be 4 4 4): (4,4,4)
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