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Hi Monks,

Why does a list assignment to a list in scalar context return the number of elements on the right side list, but NOT the last element of the left side list that has been assigned values?

I know that:

```scalar((1,3,5))     #evaluates to the last element of the list --- 5
if( (5,3,0) )       #evaluates to the last element of the list --- 0,
+thus evaluates to FALSE
\$val=(5,6,7);       #evaluates to the last element of the list --- 7

and that:

```\$ret = ((\$i, \$j, \$k)=(5,6,8,9));        #evaluates to the number of el
+ements on the right side list --- 4
if( (\$k, \$v) = ( 1, 0 ) )               #evaluates to the number of el
+ements on the right side list --- 2, thus evaluates to TRUE
while ( (\$key, \$value) = each %map )    #still evaluates to the number
+ of elements on the right side hash

Now check a scalar assignment to a scalar in scalar context: if( \$i = 0 ) which will evaluate to the value of \$i on the left side, thus evaluate to 0, thus evaluate to FALSE

but consider an example of list assignment above:

```if( (\$k, \$v) = ( 1, 0 ) )
To me, it seems like it should evaluate to the value of list (\$k, \$v) on the left side just like \$i above, thus should evaluate to the last element of list (\$k, \$v) --- \$v, thus evaluate to 0 and at last should evaluate to --- FALSE, although I know the correct answer is it will evaluate to true.

So, the question is: for what purpose are the designing principles of scalar assignment and list assignment both in scalar context completely different? Just for convenience of usage? Isn't that a bit confusing?

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