I have been trying to use the regex substitution modifier "r" to work with no success.
I finally tried running the examples from perlrequick and cannot get them to work either.
This example is from the section titled "The non-destructive modifier s///r".
$x = "I like dogs.";
$y = $x =~ s/dogs/cats/r;
print "$x $y\n"; # prints "I like dogs. I like cats."
When I run it I get this error.I get the same error using strict and declaring the variables.
Bareword found where operator expected at r.pl line 2, near "s/dogs/ca
syntax error at r.pl line 2, near "s/dogs/cats/r"
Can anyone tell me what's wrong?
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