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According to perldoc perlop, terms have the highest precedence of everything:

A TERM has the highest precedence in Perl. They include variables, quote and quote-like operators, any expression in parentheses ...

Please consider the following code.

use 5.010; sub apple { say "apple" } sub banana { say "banana" } sub cherry { say "cherry" } apple && (banana || cherry)

Given that expressions in parentheses have topmost priority, one would expect Perl to evaluate (banana || cherry) first, which would boil down to say "banana" which would return 1, and only then to evaluate apple && (1).

So the output I more or less expected is:

banana apple

However, the output I get is:

apple banana

Please shed some light on this. Why isn't the parenthesed expression evaluated first? I understand the short circuiting nature of the logical operators — for one, this explains why cherry isn't outputted at all, but I fail to understand how && seems to have higher precedence than ( EXPR ), despite the information in the documentation.


In reply to Operator precedence by muba

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