|Do you know where your variables are?|
Comment onby gods
|on Feb 11, 2000 at 00:06 UTC||Need Help??|
Adding 0 to the string "00001" forces the string to be interpreted as a number.
In your code, when you say:
You force "00001" to be treated as a number, too. What *is* interesting is *why* "00001" is treated as a number, since there is also the possibility of doing "aaa" ... "zzz" and having it work, too. So why does "00001" end up being treated as "1" by the ".." operator? Probably the perl interpreter looks at your $low and $high and decides they look like numbers.
BTW, you should not do this $low .. $high stuff - it can hang you badly if $low and $high end up to be interpreted as strings.
At least use int($low) .. int($high), to force $low and $high to be interpreted as numbers.
In reply to Re: Re: Re: Re: Finding missing elements in a sequence (code)