I am a new bie.. I have a file having 50,000 lines. I want to match a pattern. I read the whole file in an array and then match the regex. I want only the line with the first match. the code is something like :-

open( FILE, "file" ) || die ("The file not there ");
#open the file with 50,000 lines (some 1MB memory)
@list=<FILE>; # put this in an array.
close(DICTIONARY); # close the file

$regex="somebla.."; #this is the regex to be matched
@match=grep(/$regex/,@list); 
#the above line returns an array of all lines matched 
# but I want only first one !! Pity don't know how to   
# get only that..

print $match[0];
#so I get the first match of the retrned array..
#that is poor .grep has to go through the complet list 
# although I need the first match only
[download]

I request the help from perl monks.. With lot of thanks!! Pandey

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