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It looks like exponential-order to me. I added some code to sum up the number of permutations of the sets:
$bigtotal += Math::NumberCruncher::Permutation(scalar(@Num),MATRIX_D +IM); @Sol=CheckSolution(\@Num);
Here are the results:
Order 4: Maximum divisor is 416, solution is 2496-9152-1664-2080 Checked 19301184 cases 1445.940u 5.500s 27:10.91 88.9% 0+0k 0+0io 364pf+0w Order 3: Maximum divisor is 44, solution is 132-792-660 Checked 140526 cases 10.690u 0.050s 0:14.69 73.1% 0+0k 0+0io 364pf+0w Order 2:Maximum divisor is 7, solution is 21-84 Checked 820 cases 0.290u 0.010s 0:00.33 90.9% 0+0k 0+0io 364pf+0w
At that rate, order 5 will test about 1 billion cases and take over a day to run. But I think it might be feasible if bad solution sets are eliminated early.

The big problem is the permutations, which are factorial order. I would suggest picking the corner two items first. They have to have the same top digit. Then that determines the possible top digits of the rest of the rows.


In reply to Re: Re: Code to solve the "matrix formation" puzzle by tall_man
in thread Code to solve the "matrix formation" puzzle by Rhose

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