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... hv = (HV*)NEWSV(502,0); ...

... creates a new hash. We can see that the basic memory needed is 502 bytes

That's not correct: the first parameter to NEWSV is an identifier, used only for malloc debugging. It is the second parameter that provides the size, and a value of zero means "give me a new empty SV - I'll fill it in myself".

It is the following call to sv_upgrade((SV *)hv, SVt_PVHV) that actually turns this into something capable of storing a hash. In particular it allocates the struct xpvhv, defined in hv.h:

struct xpvhv { char * xhv_array; /* pointer to malloced string */ STRLEN xhv_fill; /* how full xhv_array currently is */ STRLEN xhv_max; /* subscript of last element of xhv_array */ IV xhv_keys; /* how many elements in the array */ NV xnv_nv; /* numeric value, if any */ #define xhv_placeholders xnv_nv MAGIC* xmg_magic; /* magic for scalar array */ HV* xmg_stash; /* class package */ I32 xhv_riter; /* current root of iterator */ HE *xhv_eiter; /* current entry of iterator */ PMOP *xhv_pmroot; /* list of pm's for this package */ char *xhv_name; /* name, if a symbol table */ };

Also the number of buckets does increase in powers of 2, as shown by the example code in demerphq's response. S_more_he() is not relevant to this - it is (I think) fetching a new structure from a malloc arena. The routine you want is S_hsplit() which quite early on does a nice clear:

register I32 newsize = oldsize * 2;

Hugo


In reply to Re: Re: Perl Internals: Hashes by hv
in thread Perl Internals: Hashes by Kozz

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