No code is needed. It's about the number of factors. Start with everything off and have someone go through and pull every 1nth cord. Then, someone pulls every 2nd and on with the puzzle. If a number has an even number of factors, then it will be off. If it has an odd number of factors, it will be on. The only numbers that have an odd number of factors is when one of the factors is repeated. That only happens if it's a perfect square. :-)
My criteria for good software:
- Does it work?
- Can someone else come in, make a change, and be reasonably certain no bugs were introduced?
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