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$hash{$_} ||= 1 + keys %hash for @list; $hash{$_} = $hash{$_} || 1 + keys %hash for @list;

Hmmm. I thought it was a precedence issue. Expanding slightly:

for ( @list ) { $hash{$_} ||= ( 1 + keys %hash ); } for ( @list ) { $hash{$_} = ( $hash{$_} || ( 1 + keys %hash ) ); }

I get why the second one works -- the (1 + keys %hash) evaluates first due to precedence, resulting at first in 1 + 0 = 1. Etc.

But I'm surprised at the first one, given the low precedence of assignment. It seems as if the shortcut check is happening first (with higher precedence), to see if the rest of the expression is even worth evaluating and thus autovivifying before the addition happens. (An optimization bug?)

I take that back. I'm forgetting the short-circuit. As I pondered this, the key isn't created in the hash until an assignment happens. Semantically, it looks like this is happening:

$hash{$_} ||= 1 + keys %hash; # looks more like: ( $hash{$_} = $hash{$_} ) || ( $hash{$_} = 1 + keys %hash )

-xdg

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In reply to Re: Are "$hash{$_} ||= 1 + keys %hash" and variants well defined or not? by xdg
in thread Are "$hash{$_} ||= 1 + keys %hash" and variants well defined or not? by demerphq

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