hi monks
I have a little confusion in the below code's behaviour.
I found that the builtin variable $& is not having the reliable value in it.
Initially I tried to print the values available in $` and $'. but I found a misleading answer when I print $&.
I picked this code from a very large program.
I beleive that monks can definitely clear my doubts.
$_ = foo; /foo/;
# prints "bar\n"
for (qw/bar baz/) { print "$&\n" unless /bar/; }
# prints "foo\n"
for (qw/bar baz/) { next if /bar/; print "$&\n"; }
"Keep pouring your ideas"
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