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You don't want (capturing) parentheses, you want square brackets (a character class, see perlre):

my $string = "foo / bar & etc"; my @parts = split(m# [&/] #,$string); print join("\n",@parts,"");

(Note the extra null string to tack a newline onto the "etc", and the use of a different matching delimiter to avoid the need to escape the forward slash -- the ampersand never needed to be escaped )


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In reply to Re: Why do I get regexp chars in split? by idsfa
in thread Why do I get regexp chars in split? by cormanaz

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    [Corion]: Yaerox: That's a somewhat hard problem. Encode solves the conversion part, but for guessing what encoding a file is in, that's the hard part
    [Corion]: Yaerox: There is Encode::Guess, but that needs a limited set of inputs, and it also cannot handle multiple single-byte encodings
    [Corion]: If you have a BOM, that's a really easy way to recognize UTF-8. Otherwise, you can try to decode a file from UTF-8, and if that works OK and doesn't crash, most likely the file was valid UTF-8
    [Corion]: But as "ansi" (Latin-1?) is a single-byte encoding, any file is a valid ANSI file

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