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List::Compare is the tool generally used for this sort of thing:

use strict;
use warnings;
use List::Compare;

my @AllArraysIHave = ([1,2,3,4,5], [2,3,6,7,8,8,8,9,10], [5,6,2,3]);
my $lc = List::Compare->new('-u', @AllArraysIHave);
my @result = $lc->get_intersection;

print "@result";
[download]

Prints:

3 2
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Update: speed is disapointing though (listCompareF use the functional interface):

manual: 3 2
listCompareF: 2 3
listCompare: 3 2
                Rate  listCompare listCompareF       manual
listCompare   1128/s           --         -70%         -93%
listCompareF  3822/s         239%           --         -78%
manual       17051/s        1411%         346%           --
[download]

use strict;
use warnings;
use List::Compare;
use List::Compare::Functional qw(get_intersection);
use Benchmark qw(cmpthese);

my @AllArraysIHave = ([1,2,3,4,5], [2,3,6,7,8,8,8,9,10], [5,6,2,3]);

my @result = @{manual ()};
print "manual: @result\n";

 @result = @{listCompareF ()};
print "listCompareF: @result\n";

@result = @{listCompare ()};
print "listCompare: @result\n";

cmpthese (-1,
        {
        manual => \&manual,
        listCompare => \&listCompare,
        listCompareF => \&listCompareF,
        }
    );

sub manual {
    my %intersection;
    my @result;
    foreach my $dataArray(@AllArraysIHave) {
        my %lookuptable;
        foreach(@{$dataArray}) {
            if (!$lookuptable{$_}) {
                $lookuptable{$_} = 1;
                $intersection{$_}++;
            }
        }
    }
    my $amnt = scalar(@AllArraysIHave);
    foreach my $key (keys %intersection) {
        if ($intersection{$key} == $amnt) {
            push @result, $key;
        }
    }

    return \@result;
}

sub listCompare {
    my $lc = List::Compare->new('-u', @AllArraysIHave);
    my @result = $lc->get_intersection;
    return \@result;
}

sub listCompareF {
    my @result = get_intersection ([@AllArraysIHave]);
    return \@result;
}
[download]

DWIM is Perl's answer to Gödel

In reply to Re: Getting the intersection of n collections. by GrandFather
in thread Getting the intersection of n collections. by jbrugger

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