Try your attempt with 17 and 19...
I do. Since there aren't enough digits, Math::BigFloat to the rescue:
#!/usr/bin/perl
use Math::BigFloat;
Math::BigFloat->div_scale(50);
my @values = map {
my $i = Math::BigFloat->new( 1 );
scalar $i->bdiv( $_ );
} (2,3,6,7,9,11,13,14,17,19,23);
for (@values) {
/\.\d*?(\d+?)\1/;
print "$_: $1\n"
}
__END__
0.5:
0.33333333333333333333333333333333333333333333333333: 3
0.16666666666666666666666666666666666666666666666667: 6
0.14285714285714285714285714285714285714285714285714: 142857
0.11111111111111111111111111111111111111111111111111: 1
0.090909090909090909090909090909090909090909090909091: 09
0.076923076923076923076923076923076923076923076923077: 076923
0.071428571428571428571428571428571428571428571428571: 714285
0.058823529411764705882352941176470588235294117647059: 058823529411764
+7
0.052631578947368421052631578947368421052631578947368: 052631578947368
+421
0.043478260869565217391304347826086956521739130434783: 043478260869565
+2173913
The regex is the same, though. Still missing something?
update: Oh, I see. "try with 170..." :-)
--shmem
_($_=" "x(1<<5)."?\n".q·/)Oo. G°\ /
/\_¯/(q /
---------------------------- \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}
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