When barewords are involved like in
print(foo + 2);
Perl must guess at what it means. Perl usually guesses the above means
but if foo's prototype is ($), it'll take that as a hint that you meant
print(foo() + 2);
It's the same for
Perl usually guesses the above means
but if Foo is a function, it'll take that as a hint that you meant
where Foo is presumably a function that returns a class name or an object.
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