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Strings used in numerical context as treated as decimal numbers. Use hex to convert them

Similarly, numerical literals are treated as decimal numbers. Prepend 0x.

#!/usr/bin/perl -w # File my $testString = " 00008008 000000FF 00800000"; $testString =~ s/\s+//g; my $maskResult = hex($testString) & 0x400000000000000000000000; print "Mask Result: $maskResult\n";

But those numbers are huge!

Integer overflow in hexadecimal number at line 7. Hexadecimal number > 0xffffffff non-portable at line 7. Integer overflow in hexadecimal number at line 7. Hexadecimal number > 0xffffffff non-portable at line 7. Mask Result: 4294967295

But Perl is capable of large number arithmetic using bigint/Math::BigInt.

#!/usr/bin/perl -w # File use bigint; my $testString = " 00008008 000000FF 00800000"; $testString =~ s/\s+//g; $testString = Math::BigInt->new("0x$testString"); my $maskResult = $testString & 0x400000000000000000000000; print "Mask Result: $maskResult\n";

In reply to Re: Bitwise Operator Error by ikegami
in thread Bitwise Operator Error by ravishi

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