|Why does the coderef point to the old block?
That's not a code reference, it's a scalar reference.
$string_ref is a reference to the scalar, $string. Doing a print $$string_ref;
will print out whatever's *presently* in $string.Update:
Oops ... looking at Freezy
's post in the context of the entire thread, I think I might've missed the point somewhat in my reply.
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