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One brute-force method is:
  • Store all your paths into an array.
  • Two nested loops through the array
  • Create a hash of parent directories, using index.
  • Loop through your hash and print just the leaf directories.
use strict; use warnings; my @dirs; while (<DATA>) { chomp; push @dirs, $_; } my %parents; for my $dir1 (@dirs) { for my $dir (@dirs) { if (index($dir1, $dir) == 0) { # $dir1 is a substring of $dir, starting at pos 0 $parents{$dir}++; } } } for (keys %parents) { print "$_\n" if $parents{$_} == 1 } __DATA__ /tmp/a /tmp/a/b /tmp/a/b/c /tmp/a/b/c/e /tmp/a/b/d /tmp/a/b/d/g /tmp/a/b/d/g/h /tmp/a/b/d/g/i /tmp/a/b/k
Prints:
/tmp/a/b/d/g/h /tmp/a/b/d/g/i /tmp/a/b/k /tmp/a/b/c/e
I used this technique to solve a similar problem. Hopefully, our fellow monks will provide a more elegant solution.

In reply to Re: How to Get the Last Subdirectories by toolic
in thread How to Get the Last Subdirectories by bichonfrise74

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