Think of the following: a solution to the 0-1 knapsack problem can be easily generalized to the bounded case, you just have to explicitly list the items with nr>1
. Think of my previous example as this (just written abbreviated there):
w v v/w
3 3.1 31/30 # case a
2 2 1 # case b (together with the following line)
2 2 1 # case b
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