The problem is that the list
($a .. ++$a) is not evaluating a list like you think it is. It is not doing:
$start = $a;
$end = ++$a;
for ($_ = $start; $_ <= $end; $_++) { ... }
But rather, it is evaluating its endpoints, and then constructing the list from that. That is the cause of your problem:
for (++$x .. $x++ . $x) { ... }
# starting at ++$x
# ending at $x++ . $x
# THE END HAS MODIFIED THE START
You can witness a similar result from:
print ++$x, ++$x, ++$x; # 333
You see, the arguments to a function aren't copies of the variables, but rather aliases -- by modifying ONE of the
$x's, you've modified the others as well.
Knowing this, the output of this program makes sense to me:
$x = 3;
print ++$x/$x--; # 3/4 => 0.75
Why is that? Well, the numerator is
++$x, and the denominator is
$x--; but in subtracting 1 from
$x in the denominator, we have now altered the numerator back to its original state!
I've worked out a solution to your 1 .. 12 loop, then.
for (++$x .. $x++ . $x--) { ... }
# or
for (++$....$.++.$.--) { ... }
See if you can work out why the starting point is 1.
japhy --
Perl and Regex Hacker
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