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tye, I'll try cd'ing to the dir and passing in just the pathnames.

Yes, it is really and truly too long. I'm trying to recover some length by shortening some of the directories near the start of the path in order to be able to move them without doing them one at a time by hand.

H:\so123456789012345ion/hudson/jobs/BFffs/workspace/b1234567-file-pare +nt/target/checkout/persistence-dom/src/main/java/xyz/abcd/fqq/perdom/ +pc/farmoperatingplancontributionpersistentservice/.svn/text-base/Stor,
258 characters

But you're right, the error occurs on a node in the path way before length becomes a problem. It works manually and that's what has me stumped.

I am getting "Bad File Descriptor" in the files that I don't want to change anyway, but on the ones that I want to change I get nothing. I'm debugging in komodo interactively so if there were anything there I should see it on $! as I step through the code.

In reply to Re^2: Shorten windows paths too long (trim) by gj2666
in thread Shorten windows paths too long by gj2666

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    [Eily]: the demonstration itself is fairly easy. The number of paths on a node is the sum of the numbers of paths to the two nodes above (or one node above on the edges of the triangle)
    [Eily]: since the value of a node is also the sum from the two nodes above, you just have to demonstrate that the equality is true at the top of the triangle
    [Discipulus]: yes Eily, thanks oiskuu but i dont get it.. ;=( maybe I'll ask a SOPW
    [LanX]: all combinations with same amount of left and right?
    [Eily]: if you want to store in a structure with the coordinates as key, arrays might do, since the keys are going to be 0..n
    [LanX]: (Pascale path)
    [Eily]: paths like that
    [Discipulus]: yes Eily++ (very keen) I want to integrate my project with a 17th experiments. I want to colorize in sequence all paths
    [oiskuu]: Yeah, modifry the recursive func combinations() to return not the number, but the paths themselves.
    [Eily]: Discipulus I'd do that by starting from the bottom node I think. That way it can inherit the paths from the two nodes above (and so on, recursively)

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