Eh, perhaps on *your* system, but look at this:
$ perl -le 'print \\///\\\//'
What the result of \\///\\\// is depends on
how memory is alloced. It'll depend on your malloc
(which could be the Perl supplied, or the system one, depending
on how Perl was build); it'll hand out addresses using some
algorithm, based on various factors. Don't assume that when
you run it once on your system, it will be the same universally.
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