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This shoudl be a little quicker. It uses a bit vector rather than a hash which is a bit quicker to start. It then scans the bit vector 64-bits at a time until it finds a possibility and then by bit until it isolates the next value:

#! perl -slw use strict; my @ports = ( 50000..51545,51549,51555..51999, 65535 ); my $vec = ''; vec( $vec, $_, 1 ) = 1 for 0 .. 50_000, @ports; sub nextFreePort { no warnings 'portable'; my $open_port; my $t = int( length( $vec ) / 8 ); my $n = 782; ++$n while $n <= $t and vec( $vec, $n, 64 ) == 1844674407370955161 +5; $n *= 64; vec( $vec, $_, 1 ) or $open_port = $_ and last for $n .. $n + 64; vec( $vec, $open_port, 1 ) = 1; return $open_port; } my $next_port = nextFreePort(); print $next_port; __END__ c:\test> 51546

Worst case of only 65535 being available, it does 242+63 tests+incs, rather than 15500.

If I were writing this in assembler, I'd test lo/hi 32-bit; lo/hi 16-bit; lo/hi 8-bit before hitting the bits individually thereby reducing the 63 tests/incs to 10.

It require 8k of string which is quite possibly smaller than your hash. That coudl be reduced further by not storing bits for 0 .. 50_000.

It's a POC. I haven't tested the edge cases.

Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
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In reply to Re: fastest way to compare two arrays by BrowserUk
in thread fastest way to compare two arrays by krusty

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