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I asked indirectly a question in Re: Length obfuscation that I'd like to extend here to a wider audience:

Is there a means to obtain the translation seed "n0123.." permutationally?

The translation seed allows to shift any permutational string to the right by one sign. What I mean by permutationally is that you can obtain your result with the help of the function perm() primarily. For example the natural suite "0123..n" can be obtained permutationally by repeating y = perm(x,x) and then y1 = perm(y,x) enough times with y1,y2,etc. for any permutation x. In Re: Length obfuscation I think that with some more efforts, the function comp() could be reduced to a particular composition of calls to perm().

I know it's more a math question than a Perl one but I found that it was not a bad idea to ask for the wisdom of Perl monks - who are used to deal with generic problems of this kind after all. Getting the translation seed permutationally should make a system of permutational functions more efficient.

```sub perm {
my (\$target,\$agent) = @_;
my @targ = split //,\$target;
my @perm = split //,\$agent;
my \$res;
for (my \$i = 0; \$i < (@perm); \$i++){ \$res .= \$perm[\$targ[\$i]] }
return \$res;
}

Comment:

By "permutation" we understand any permutation of the distinct elements pertaining to the natural - or well ordered - suite "01..n". The function perm() above accepts two permutations in the same base n+1 < 11. For this function, "012", "3102", "7465023198", are valid permutations when "013", "3112" or "7465023198A" are not.

In reply to How to get the translation seed? by emilbarton

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