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OK. In the while loop, I create a hash whose keys are the words from the list (there is no value, that's why the undef).

Then, I go through the words one by one. For each word, I try all the positions and all possible lengths of its subwords (and I skip the maximal length at position 0, because that would breake the rule #2). For each subword, I do nothing if it has already been printed out (each word should be reported just once). I do nothing if rules #3 or #4 apply. Otherwise, I check whether the subword is itself on the list of words. If it is, I report it and book it as such. And that's it.

The basic idea was this: Comparing each word to all other words would take ages. There would be many comparisons of words that are totally incompatible. How can I reduce the number of comparisons? I do not need all the words, I only need those that are possible for the given word.

As I read the code know, I think it might be optimized a bit further. Instead of caching the reported subwords, you can cache the tested ones (i.e. move the undef three lines up, before the "if"). %reported should be renamed to %checked then.

In reply to Re^9: Words in Words by choroba
in thread Words in Words by sarchasm

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    [1nickt]: karlgoethebier Thank you!! How could I not have ever heard of this musician?
    [choroba]: thezip should be ok.
    [thezip]: It seemed so, choroba, but I don't want to confuse anyone (especially myself!)
    [choroba]: thezip unless something like this happens to you.
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    [choroba]: also, I didn't have a smart phone at that time

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