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Let's look at the  /[$i]{$_}/ regex. The  [$i] defines a character class that matches whatever  $i interpolates as a string into the regex. In this case,  $i never changes: it is always the number 0 which interpolates as the '0' (zero) character, so the character class matches a '0' character and nothing else.

The  {$_} quantifier of the  [0] character class (which is the same as '0') takes on the values that  $_ interpolates into the regex on each iteration of the for-loop. These values are from the  @nums array and happen to be  (2, 0, 2, 0) successively.

So the  [$i]{$_} regex expression alternates between  0{2} and  0{0}. That's all there is to the regex. The  0{2} regex does not match (twice!) against the  $num string of '2020' because that string does not have two consecutive '0' characters anywhere in it. The  0{0} regex does match (again, twice) because there is a place in the '2020' string where there is no '0' character.

See perlre, perlretut, perlrequick.

Update: Rats. Missed the  $i++; statement. Of course, the analysis of jwkrahn is correct, while mine is wandering up and down in the street outside the ballpark. .oO(But was  $i++; present in the original original post, the one to which I replied? The more I think about it, the more I think it wasn't!)

In reply to Re: regex not working by AnomalousMonk
in thread regex not working by andrewbriggs

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