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Hi monk, I have a string which contains data of a person delimited by '%'. The third field in the string represents 'ID' tag, I want to extract all thr names which has ID tag starting with 'A'. For example $data variable may contain :

$data = "Johnson%Andrew%AX321%Engineer" ; $data = "Smith%John%BC142%Alberta";

I am using :

print "$2 $1\n" if m/^(.*?)%(.*?)%A/;

But this is giving me

Andrew Johnson ## output Ok John%BC142Smith ## Wrong

But I don't want this. The second half of the regex does not say match up to next % and then match 'A'. Instead it says match upto the next % which is followed by 'A'. Hence for the second $data it is getting past the second % and fetching John%BC142Smith Please help. Thanks.


In reply to Regex help needed by ghosh123

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