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Another recursive solution using a subroutine that takes a block of code to execute against a "chunked" list.

use strict; use warnings; use 5.010; sub groupsOf (&$@); my @list = ( q{a} .. q{z} ); say for groupsOf { qq{@_,} } 5, @list; say for groupsOf { qq{@_,} } 7, @list; sub groupsOf (&$@) { my $rcToRun = shift; my $groupsOf = shift; my $rcDoIt; $rcDoIt = sub { $rcToRun->( map shift, 1 .. ( @_ < $groupsOf ? @_ : $groupsOf ) ), @_ ? &$rcDoIt : (); }; &$rcDoIt; }

I hope this is of interest.

Update: Oops, forgot to post the output :-(

a b c d e, f g h i j, k l m n o, p q r s t, u v w x y, z, a b c d e f g, h i j k l m n, o p q r s t u, v w x y z,

Cheers,

JohnGG


In reply to Re: How to return a list using recursion? by johngg
in thread How to return a list using recursion? by dr.jekyllandme

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