comment on

What I understand from this code is: -

First we are converting the expression into an array or list.. Now, had we printed out that list or array, it would have printed out its address.. So, we have added an '@' before it to get an array.. Now, because we are not using a reference variable to this list, we have used a curly braces before using '@'

Have I interpreted it correct.. Is this what happens in Perl?? Or can I get a better explanation of what is happening there?

In reply to Re^2: How can we interpolate an expression?? by Rohit Jain
in thread How can we interpolate an expression?? by Rohit Jain

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