Perl Gods,

I am generating a CSV file with the first 2 columns in the Epoch time format. I want to be able to run a script that converts and replaces these fields with a human readable date. How would I got about doing that - I'm just learning Perl so if you could explain it to me like I'm 5 that'd be great haha!

CSV:

1345752662, 1345752673, CLOSED, CRITICAL, Other fields etc
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What I want:

Thu Aug 23 2012 15:11:02, Thu Aug 23 2012 15:11:13, CLOSED, CRITICAL, 
+ETC
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***************UPDATE:*****************

Here is the solution I came up with thanks to you guys!

#!/usr/bin/perl
use strict;
use Text::CSV;
use Tie::File;


my (@records, @removed);
tie @records, 'Tie::File', "test.csv";
@removed = splice(@records,0,2);
print join ("\n", @records);
untie @records;

my $file = 'test.csv';

my $csv = Text::CSV->new();

open (CSV, "<", $file) or die $!;
open (MYFILE, '>>convertedDate.csv');

#Column Headers
#First 2 are in Epoch time
print MYFILE "Arrival, Modified Date, Severity, Status, TicketID, Mess
+age\n";
close (MYFILE);

while (<CSV>) 
{
    if ($csv->parse($_)) 
    {
      open (MYFILE, '>>convertedDate.csv');       
      my @columns = $csv->fields();
      #I know this next line isn't so elegant
      print MYFILE scalar(localtime(@columns[0])) . "," . scalar(local
+time(@columns[1])) . ",\"" . @columns[2] . "\",\"" . @columns[3] . "\
+",\"" . @columns[4] . "\",\"" . @columns[5] . "\"";
      print MYFILE "\n";
      close (MYFILE);
    }
    else 
    {
      my $err = $csv->error_input;
      print "Failed to parse line: $err";
    }
}
close CSV;
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