Re: Re: How do I write subs that take bare blocks as args?

Hey, good idea! Except, to work the same as my example, it needs to be:

if ( ( grep { $_->price <= 1000 } @product_list  ) == @product_list )
{
    # do stuff
}
[download]

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Re^3: How do I write subs that take bare blocks as args? by Aristotle (Chancellor) on Jun 28, 2002 at 16:03 UTC
Why so complicated? :) `if(not grep { $_->price > 1000 } @product_list) { # do stuff }` [download] Update: `my @p = (0,2,4,5,2,5,7,7); print "1: none\n" if not grep { $_ > 1000 } @p; push @p, 1002; print "2: none\n" if not grep { $_ > 1000 } @p; =output 1: none` [download] `____________` Makeshifts last the longest.	[reply] [d/l] [select]
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Re^3: How do I write subs that take bare blocks as args? by flounder99 (Friar) on Jun 28, 2002 at 15:31 UTC
You are right. In my example the `{ #do stuff }` block will get executed if any of the members of `@product_list` pass the conditions. You want to know if all members pass. IIRC won't perl6 have some kind of `any` and `all` builtins? -- flounder	[reply] [d/l] [select]
Re: Re^3: How do I write subs that take bare blocks as args? by theorbtwo (Prior) on Jun 28, 2002 at 20:44 UTC
It will. But Quantum::Superpositions will give them to you now. (Warning: This module is superfreaky.) We are using here a powerful strategy of synthesis: wishful thinking. -- The Wizard Book	[reply]