Re: Re: Re: checking the end of line

[dimmesdale]

Do I?

For a string 'stuff_here_then_12' your version captures the 1. It depends if that's what the user wants. Of course there's probably a better way to do this /(\d)\d*$/ comes to mind (and /(\d)+$/ if the user wants the last digit, or even better /(\d)$/ .. updated .. well, if just the last digit is desired and it's always known to be a digit substr could be used more effeciently -- of course, you have to be sure of your data)

I was under the impressino that he wanted the entire 12 returned.

[I0]

For a string 'stuff_here_then_12' ($path =~ /(\d+)$/)[0] captures the 12

[dimmesdale]

$1 captures 12, you are right. However, you do an array slice thing with the [0] part -- which on my machine perl 5.6.1 AS build 633 produces an error; I have to move the parentheses around the regex itself. And when you print it, it shows a 1 on my computer. I just don't see the need for the [0]

[I0]

What error does it produce on your machine? On mine, the array slice is necessary to put the regex in list context so that it returns the captured string instead of the true or false value it returns in scalar context